穷举法
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#include <stdio.h>
int main(int argc, char *argv[])
{
int k, x, y;
int i;
k = 12;
for (x=k+1; x<=2*k; x++) {
y = k*x/(x-k);
if (y*(x-k)==k*x)
printf("1/%d=1/%d+1/%dn", k, x, y);
}
return 0;
}#include <stdio.h>
int main(int argc, char *argv[])
{
int k, x, y;
int i;
k = 12;
for (x=k+1; x<=2*k; x++) {
......
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