新思维：C语言程序设计

1x1= 1
1x2= 2 2x2= 4
1x3= 3 2x3= 6 3x3= 9
1x4= 4 2x4= 8 3x4=12 4x4=16
1x5= 5 2x5=10 3x5=15 4x5=20 5x5=25
1x6= 6 2x6=12 3x6=18 4x6=24 5x6=30 6x6=36
1x7= 7 2x7=14 3x7=21 4x7=28 5x7=35 6x7=42 7x7=49
1x8= 8 2x8=16 3x8=24 4x8=32 5x8=40 6x8=48 7x8=56 8x8=64
1x9= 9 2x9=18 3x9=27 4x9=36 5x9=45 6x9=54 7x9=63 8x9=72 9x9=81

1x1= 1 1x2= 2 2x2= 4 1x3= 3 2x3= 6 3x3= 9 1x4= 4 2x4= 8 3x4=12 4x4=16 1x5= 5 2x5=10 3x5=15 4x5=20 5x5=25 1x6= 6 2x6=12 3x6=18 4x6=24 5x6=30 6x6=36 1x7= 7 2x7=14 3x7=21 4x7=28 5x7=35 6x7=42 7x7=49 1x8= 8 2x8=16 3x8=24 4x8=32 5x8=40 6x8=48 7x8=56 8x8=64 1x9= 9 2x9=18 3x9=27 4x9=36 5x9=45 6x9=54 7x9=63 8x9=72 9x9=81

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#include <stdio.h>
int main()
{
    int i, j;
    i=5;
    for (j=1; j<=i; j++) 
      printf("%dx%d=%2d ", j, i, j*i);
    printf("\n");     
    return 0;
}

#include <stdio.h> int main() { int i, j; i=5; for (j=1; j<=i; j++) printf("%dx%d=%2d ", j, i, j*i); printf("\n"); return 0; }

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#include <stdio.h>
int main()
{
    int i,j;
    for (i=1; i<=9; i++) {
        for (j=1; j<=i; j++)
            printf("%dx%d=%2d ", j, i, j*i);
        printf("\n");
    }
    return 0;
}

#include <stdio.h> int main() { int i,j; for (i=1; i<=9; i++) { for (j=1; j<=i; j++) printf("%dx%d=%2d ", j, i, j*i); printf("\n"); } return 0; }